Base | Representation |
---|---|
bin | 1110001100001000001001… |
… | …00000100001101111011001 |
3 | 11002110222102121222012211212 |
4 | 13012010010200201233121 |
5 | 13042212232314303423 |
6 | 150210244415432505 |
7 | 6400225515461534 |
oct | 706040440415731 |
9 | 132428377865755 |
10 | 31203013041113 |
11 | 9a4013a445571 |
12 | 35bb429b25735 |
13 | 145457c026304 |
14 | 79c33bb13a1b |
15 | 3919de282578 |
hex | 1c6104821bd9 |
31203013041113 has 2 divisors, whose sum is σ = 31203013041114. Its totient is φ = 31203013041112.
The previous prime is 31203013041089. The next prime is 31203013041127. The reversal of 31203013041113 is 31114031030213.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 30727365573529 + 475647467584 = 5543227^2 + 689672^2 .
It is a cyclic number.
It is not a de Polignac number, because 31203013041113 - 222 = 31203008846809 is a prime.
It is not a weakly prime, because it can be changed into another prime (31203013041313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15601506520556 + 15601506520557.
It is an arithmetic number, because the mean of its divisors is an integer number (15601506520557).
Almost surely, 231203013041113 is an apocalyptic number.
It is an amenable number.
31203013041113 is a deficient number, since it is larger than the sum of its proper divisors (1).
31203013041113 is an equidigital number, since it uses as much as digits as its factorization.
31203013041113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 31203013041113 its reverse (31114031030213), we get a palindrome (62317044071326).
The spelling of 31203013041113 in words is "thirty-one trillion, two hundred three billion, thirteen million, forty-one thousand, one hundred thirteen".
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