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31203013041113 is a prime number
BaseRepresentation
bin1110001100001000001001…
…00000100001101111011001
311002110222102121222012211212
413012010010200201233121
513042212232314303423
6150210244415432505
76400225515461534
oct706040440415731
9132428377865755
1031203013041113
119a4013a445571
1235bb429b25735
13145457c026304
1479c33bb13a1b
153919de282578
hex1c6104821bd9

31203013041113 has 2 divisors, whose sum is σ = 31203013041114. Its totient is φ = 31203013041112.

The previous prime is 31203013041089. The next prime is 31203013041127. The reversal of 31203013041113 is 31114031030213.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 30727365573529 + 475647467584 = 5543227^2 + 689672^2 .

It is a cyclic number.

It is not a de Polignac number, because 31203013041113 - 222 = 31203008846809 is a prime.

It is not a weakly prime, because it can be changed into another prime (31203013041313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15601506520556 + 15601506520557.

It is an arithmetic number, because the mean of its divisors is an integer number (15601506520557).

Almost surely, 231203013041113 is an apocalyptic number.

It is an amenable number.

31203013041113 is a deficient number, since it is larger than the sum of its proper divisors (1).

31203013041113 is an equidigital number, since it uses as much as digits as its factorization.

31203013041113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 31203013041113 its reverse (31114031030213), we get a palindrome (62317044071326).

The spelling of 31203013041113 in words is "thirty-one trillion, two hundred three billion, thirteen million, forty-one thousand, one hundred thirteen".