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31203020130041 is a prime number
BaseRepresentation
bin1110001100001000001001…
…11011100100011011111001
311002110222110010022101000202
413012010010323210123321
513042212241123130131
6150210245231411545
76400225632645134
oct706040473443371
9132428403271022
1031203020130041
119a40143447591
1235bb430383bb5
131454580638b46
1479c33ca3b21b
153919debd2bcb
hex1c6104ee46f9

31203020130041 has 2 divisors, whose sum is σ = 31203020130042. Its totient is φ = 31203020130040.

The previous prime is 31203020130017. The next prime is 31203020130083. The reversal of 31203020130041 is 14003102030213.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 30142614472441 + 1060405657600 = 5490229^2 + 1029760^2 .

It is a cyclic number.

It is not a de Polignac number, because 31203020130041 - 222 = 31203015935737 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 31203020129995 and 31203020130022.

It is not a weakly prime, because it can be changed into another prime (31203020130091) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15601510065020 + 15601510065021.

It is an arithmetic number, because the mean of its divisors is an integer number (15601510065021).

Almost surely, 231203020130041 is an apocalyptic number.

It is an amenable number.

31203020130041 is a deficient number, since it is larger than the sum of its proper divisors (1).

31203020130041 is an equidigital number, since it uses as much as digits as its factorization.

31203020130041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 31203020130041 its reverse (14003102030213), we get a palindrome (45206122160254).

The spelling of 31203020130041 in words is "thirty-one trillion, two hundred three billion, twenty million, one hundred thirty thousand, forty-one".