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312031200000 = 283551373137
BaseRepresentation
bin1001000101001101000…
…00100100001100000000
31002211101222202022110010
410202212200210030000
520103014441400000
6355202315304520
731354265303232
oct4424640441400
91084358668403
10312031200000
111103715289a3
125058274b140
1323569598670
1411160d62252
1581b3a43d50
hex48a6824300

312031200000 has 864 divisors, whose sum is σ = 1141437068352. Its totient is φ = 75202560000.

The previous prime is 312031199969. The next prime is 312031200001. The reversal of 312031200000 is 2130213.

It is a happy number.

It is a Harshad number since it is a multiple of its sum of digits (12).

It is not an unprimeable number, because it can be changed into a prime (312031200001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 2277599932 + ... + 2277600068.

It is an arithmetic number, because the mean of its divisors is an integer number (1321107718).

Almost surely, 2312031200000 is an apocalyptic number.

312031200000 is a gapful number since it is divisible by the number (30) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 312031200000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (570718534176).

312031200000 is an abundant number, since it is smaller than the sum of its proper divisors (829405868352).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

312031200000 is an equidigital number, since it uses as much as digits as its factorization.

312031200000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 267 (or 233 counting only the distinct ones).

The product of its (nonzero) digits is 36, while the sum is 12.

Adding to 312031200000 its reverse (2130213), we get a palindrome (312033330213).

It can be divided in two parts, 3120 and 31200000, that multiplied together give a square (97344000000 = 3120002).

The spelling of 312031200000 in words is "three hundred twelve billion, thirty-one million, two hundred thousand".