Base | Representation |
---|---|
bin | 1110001100001000010111… |
… | …01010100001000110000101 |
3 | 11002110222201222212212020220 |
4 | 13012010023222201012011 |
5 | 13042213004033203141 |
6 | 150210304345014553 |
7 | 6400231504120632 |
oct | 706041352410605 |
9 | 132428658785226 |
10 | 31203133100421 |
11 | 9a401a1197937 |
12 | 35bb462184459 |
13 | 145459ab71219 |
14 | 79c34da47189 |
15 | 3919e9a9a766 |
hex | 1c610baa1185 |
31203133100421 has 24 divisors (see below), whose sum is σ = 43465103853024. Its totient is φ = 19896821226720.
The previous prime is 31203133100393. The next prime is 31203133100423. The reversal of 31203133100421 is 12400133130213.
It is not a de Polignac number, because 31203133100421 - 25 = 31203133100389 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 31203133100391 and 31203133100400.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (31203133100423) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 39991275 + ... + 40764056.
It is an arithmetic number, because the mean of its divisors is an integer number (1811045993876).
Almost surely, 231203133100421 is an apocalyptic number.
It is an amenable number.
31203133100421 is a deficient number, since it is larger than the sum of its proper divisors (12261970752603).
31203133100421 is an equidigital number, since it uses as much as digits as its factorization.
31203133100421 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 80755489 (or 80755430 counting only the distinct ones).
The product of its (nonzero) digits is 1296, while the sum is 24.
Adding to 31203133100421 its reverse (12400133130213), we get a palindrome (43603266230634).
The spelling of 31203133100421 in words is "thirty-one trillion, two hundred three billion, one hundred thirty-three million, one hundred thousand, four hundred twenty-one".
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