Base | Representation |
---|---|
bin | 1110001100001000011000… |
… | …01110000000100000010001 |
3 | 11002110222202122101112112002 |
4 | 13012010030032000200101 |
5 | 13042213013423412423 |
6 | 150210305320243345 |
7 | 6400231646160251 |
oct | 706041416004021 |
9 | 132428678345462 |
10 | 31203142404113 |
11 | 9a401a6471939 |
12 | 35bb465310555 |
13 | 145459ca7ab74 |
14 | 79c350d89961 |
15 | 3919ea7d7228 |
hex | 1c610c380811 |
31203142404113 has 2 divisors, whose sum is σ = 31203142404114. Its totient is φ = 31203142404112.
The previous prime is 31203142404041. The next prime is 31203142404121. The reversal of 31203142404113 is 31140424130213.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 16039960920064 + 15163181484049 = 4004992^2 + 3893993^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-31203142404113 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (31203142404143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15601571202056 + 15601571202057.
It is an arithmetic number, because the mean of its divisors is an integer number (15601571202057).
Almost surely, 231203142404113 is an apocalyptic number.
It is an amenable number.
31203142404113 is a deficient number, since it is larger than the sum of its proper divisors (1).
31203142404113 is an equidigital number, since it uses as much as digits as its factorization.
31203142404113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 31203142404113 its reverse (31140424130213), we get a palindrome (62343566534326).
The spelling of 31203142404113 in words is "thirty-one trillion, two hundred three billion, one hundred forty-two million, four hundred four thousand, one hundred thirteen".
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