Base | Representation |
---|---|
bin | 100011011110010110010110… |
… | …1000001101001111011001011 |
3 | 1111220211012101112122221100221 |
4 | 1012330230231001221323023 |
5 | 311344333000123232113 |
6 | 3023350345145210511 |
7 | 122503512631360102 |
oct | 10674545501517313 |
9 | 1456735345587327 |
10 | 312034424430283 |
11 | 90473068963305 |
12 | 2abb6441490a37 |
13 | 105159489c4579 |
14 | 570a7922d7039 |
15 | 2611ae8a1a98d |
hex | 11bcb2d069ecb |
312034424430283 has 2 divisors, whose sum is σ = 312034424430284. Its totient is φ = 312034424430282.
The previous prime is 312034424430181. The next prime is 312034424430307. The reversal of 312034424430283 is 382034424430213.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 312034424430283 - 241 = 309835401174731 is a prime.
It is a super-3 number, since 3×3120344244302833 (a number of 44 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (312034424430383) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156017212215141 + 156017212215142.
It is an arithmetic number, because the mean of its divisors is an integer number (156017212215142).
Almost surely, 2312034424430283 is an apocalyptic number.
312034424430283 is a deficient number, since it is larger than the sum of its proper divisors (1).
312034424430283 is an equidigital number, since it uses as much as digits as its factorization.
312034424430283 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1327104, while the sum is 43.
Adding to 312034424430283 its reverse (382034424430213), we get a palindrome (694068848860496).
The spelling of 312034424430283 in words is "three hundred twelve trillion, thirty-four billion, four hundred twenty-four million, four hundred thirty thousand, two hundred eighty-three".
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