31204430121433 has 2 divisors, whose sum is σ = 31204430121434. Its totient is φ = 31204430121432.

The previous prime is 31204430121419. The next prime is 31204430121443. The reversal of 31204430121433 is 33412103440213.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 17787542430784 + 13416887690649 = 4217528^2 + 3662907^2 .

It is an emirp because it is prime and its reverse (33412103440213) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-31204430121433 is a prime.

It is a super-2 number, since 2×31204430121433² (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 31204430121395 and 31204430121404.

It is not a weakly prime, because it can be changed into another prime (31204430121443) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15602215060716 + 15602215060717.

It is an arithmetic number, because the mean of its divisors is an integer number (15602215060717).

Almost surely, 2^{31204430121433} is an apocalyptic number.

It is an amenable number.

31204430121433 is a deficient number, since it is larger than the sum of its proper divisors (1).

31204430121433 is an equidigital number, since it uses as much as digits as its factorization.

31204430121433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 31204430121433 its reverse (33412103440213), we get a palindrome (64616533561646).

The spelling of 31204430121433 in words is "thirty-one trillion, two hundred four billion, four hundred thirty million, one hundred twenty-one thousand, four hundred thirty-three".