Base | Representation |
---|---|
bin | 1011100111111111… |
… | …0000110110010001 |
3 | 22001110202211102021 |
4 | 2321333300312101 |
5 | 22342322000423 |
6 | 1233351051441 |
7 | 140220545653 |
oct | 27177606621 |
9 | 8043684367 |
10 | 3120500113 |
11 | 1361493a15 |
12 | 731070b81 |
13 | 3a9654c93 |
14 | 2186126d3 |
15 | 133e4795d |
hex | b9ff0d91 |
3120500113 has 2 divisors, whose sum is σ = 3120500114. Its totient is φ = 3120500112.
The previous prime is 3120500107. The next prime is 3120500167. The reversal of 3120500113 is 3110050213.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2641240449 + 479259664 = 51393^2 + 21892^2 .
It is an emirp because it is prime and its reverse (3110050213) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 3120500113 - 221 = 3118402961 is a prime.
It is not a weakly prime, because it can be changed into another prime (3120506113) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1560250056 + 1560250057.
It is an arithmetic number, because the mean of its divisors is an integer number (1560250057).
Almost surely, 23120500113 is an apocalyptic number.
It is an amenable number.
3120500113 is a deficient number, since it is larger than the sum of its proper divisors (1).
3120500113 is an equidigital number, since it uses as much as digits as its factorization.
3120500113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 90, while the sum is 16.
The square root of 3120500113 is about 55861.4367251685. The cubic root of 3120500113 is about 1461.3067853717.
Adding to 3120500113 its reverse (3110050213), we get a palindrome (6230550326).
The spelling of 3120500113 in words is "three billion, one hundred twenty million, five hundred thousand, one hundred thirteen".
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