312100104023 has 4 divisors (see below), whose sum is σ = 316495880208. Its totient is φ = 307704327840.

The previous prime is 312100103981. The next prime is 312100104049. The reversal of 312100104023 is 320401001213.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 320401001213 = 47 ⋅6817042579.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-312100104023 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 312100103992 and 312100104010.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (312100104923) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2197887986 + ... + 2197888127.

It is an arithmetic number, because the mean of its divisors is an integer number (79123970052).

Almost surely, 2^312100104023 is an apocalyptic number.

312100104023 is a deficient number, since it is larger than the sum of its proper divisors (4395776185).

312100104023 is an equidigital number, since it uses as much as digits as its factorization.

312100104023 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4395776184.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 312100104023 its reverse (320401001213), we get a palindrome (632501105236).

The spelling of 312100104023 in words is "three hundred twelve billion, one hundred million, one hundred four thousand, twenty-three".