Base | Representation |
---|---|
bin | 100011011110110110000100… |
… | …0011100101011010001000011 |
3 | 1111221001201011221202012121211 |
4 | 1012331230020130223101003 |
5 | 311401441440214432121 |
6 | 3023441531213030551 |
7 | 122511443435216641 |
oct | 10675541034532103 |
9 | 1457051157665554 |
10 | 312102530233411 |
11 | 90499a37903215 |
12 | 2b007689a85457 |
13 | 1051c1b088a868 |
14 | 570dbb3516191 |
15 | 2613782bb7ce1 |
hex | 11bdb0872b443 |
312102530233411 has 2 divisors, whose sum is σ = 312102530233412. Its totient is φ = 312102530233410.
The previous prime is 312102530233343. The next prime is 312102530233499. The reversal of 312102530233411 is 114332035201213.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 312102530233411 - 213 = 312102530225219 is a prime.
It is not a weakly prime, because it can be changed into another prime (312102530233211) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156051265116705 + 156051265116706.
It is an arithmetic number, because the mean of its divisors is an integer number (156051265116706).
Almost surely, 2312102530233411 is an apocalyptic number.
312102530233411 is a deficient number, since it is larger than the sum of its proper divisors (1).
312102530233411 is an equidigital number, since it uses as much as digits as its factorization.
312102530233411 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12960, while the sum is 31.
Adding to 312102530233411 its reverse (114332035201213), we get a palindrome (426434565434624).
The spelling of 312102530233411 in words is "three hundred twelve trillion, one hundred two billion, five hundred thirty million, two hundred thirty-three thousand, four hundred eleven".
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