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31211031122113 is a prime number
BaseRepresentation
bin1110001100010111000100…
…11011000101000011000001
311002111202010102101221012211
413012023202123011003001
513042330142431401423
6150214052203022121
76400631306156143
oct706134233050301
9132452112357184
1031211031122113
119a43584442497
123600aa720a941
13145525922a23b
1479c89c966c93
15391d0d15010d
hex1c62e26c50c1

31211031122113 has 2 divisors, whose sum is σ = 31211031122114. Its totient is φ = 31211031122112.

The previous prime is 31211031122099. The next prime is 31211031122153. The reversal of 31211031122113 is 31122113011213.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 31009172313744 + 201858808369 = 5568588^2 + 449287^2 .

It is a cyclic number.

It is not a de Polignac number, because 31211031122113 - 213 = 31211031113921 is a prime.

It is not a weakly prime, because it can be changed into another prime (31211031122153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15605515561056 + 15605515561057.

It is an arithmetic number, because the mean of its divisors is an integer number (15605515561057).

Almost surely, 231211031122113 is an apocalyptic number.

It is an amenable number.

31211031122113 is a deficient number, since it is larger than the sum of its proper divisors (1).

31211031122113 is an equidigital number, since it uses as much as digits as its factorization.

31211031122113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 216, while the sum is 22.

Adding to 31211031122113 its reverse (31122113011213), we get a palindrome (62333144133326).

The spelling of 31211031122113 in words is "thirty-one trillion, two hundred eleven billion, thirty-one million, one hundred twenty-two thousand, one hundred thirteen".