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3121122453131 is a prime number
BaseRepresentation
bin101101011010110001011…
…001010010011010001011
3102001101011101112102011202
4231122301121102122023
5402114024322000011
610345453542014415
7441331216056434
oct55326131223213
912041141472152
103121122453131
11aa372a291511
12424a8971740b
13198422429b07
14ab0c534448b
15562c301823b
hex2d6b165268b

3121122453131 has 2 divisors, whose sum is σ = 3121122453132. Its totient is φ = 3121122453130.

The previous prime is 3121122453109. The next prime is 3121122453149. The reversal of 3121122453131 is 1313542211213.

3121122453131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3121122453131 is a prime.

It is a super-2 number, since 2×31211224531312 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 3121122453094 and 3121122453103.

It is not a weakly prime, because it can be changed into another prime (3121122453101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1560561226565 + 1560561226566.

It is an arithmetic number, because the mean of its divisors is an integer number (1560561226566).

Almost surely, 23121122453131 is an apocalyptic number.

3121122453131 is a deficient number, since it is larger than the sum of its proper divisors (1).

3121122453131 is an equidigital number, since it uses as much as digits as its factorization.

3121122453131 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 4320, while the sum is 29.

Adding to 3121122453131 its reverse (1313542211213), we get a palindrome (4434664664344).

The spelling of 3121122453131 in words is "three trillion, one hundred twenty-one billion, one hundred twenty-two million, four hundred fifty-three thousand, one hundred thirty-one".