Base | Representation |
---|---|
bin | 1001000101010110110… |
… | …01000100011011100001 |
3 | 1002211121200220022220222 |
4 | 10202223121010123201 |
5 | 20103201424332433 |
6 | 355214403212425 |
7 | 31356311520032 |
oct | 4425331043341 |
9 | 1084550808828 |
10 | 312113120993 |
11 | 1104037a13a3 |
12 | 505a6077115 |
13 | 2358054c21b |
14 | 1116bba8a89 |
15 | 81bad26b98 |
hex | 48ab6446e1 |
312113120993 has 2 divisors, whose sum is σ = 312113120994. Its totient is φ = 312113120992.
The previous prime is 312113120971. The next prime is 312113121029. The reversal of 312113120993 is 399021311213.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 221169862369 + 90943258624 = 470287^2 + 301568^2 .
It is a cyclic number.
It is not a de Polignac number, because 312113120993 - 26 = 312113120929 is a prime.
It is not a weakly prime, because it can be changed into another prime (312113120953) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156056560496 + 156056560497.
It is an arithmetic number, because the mean of its divisors is an integer number (156056560497).
Almost surely, 2312113120993 is an apocalyptic number.
It is an amenable number.
312113120993 is a deficient number, since it is larger than the sum of its proper divisors (1).
312113120993 is an equidigital number, since it uses as much as digits as its factorization.
312113120993 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8748, while the sum is 35.
The spelling of 312113120993 in words is "three hundred twelve billion, one hundred thirteen million, one hundred twenty thousand, nine hundred ninety-three".
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