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312113120999 = 794939264451
BaseRepresentation
bin1001000101010110110…
…01000100011011100111
31002211121200220022221012
410202223121010123213
520103201424332444
6355214403212435
731356311520041
oct4425331043347
91084550808835
10312113120999
111104037a13a9
12505a607711b
132358054c224
141116bba8a91
1581bad26b9e
hex48ab6446e7

312113120999 has 4 divisors (see below), whose sum is σ = 312152393400. Its totient is φ = 312073848600.

The previous prime is 312113120993. The next prime is 312113121029. The reversal of 312113120999 is 999021311213.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 312113120999 - 220 = 312112072423 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (312113120993) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19624277 + ... + 19640174.

It is an arithmetic number, because the mean of its divisors is an integer number (78038098350).

Almost surely, 2312113120999 is an apocalyptic number.

312113120999 is a deficient number, since it is larger than the sum of its proper divisors (39272401).

312113120999 is an equidigital number, since it uses as much as digits as its factorization.

312113120999 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 39272400.

The product of its (nonzero) digits is 26244, while the sum is 41.

It can be divided in two parts, 312 and 113120999, that added together give a palindrome (113121311).

The spelling of 312113120999 in words is "three hundred twelve billion, one hundred thirteen million, one hundred twenty thousand, nine hundred ninety-nine".

Divisors: 1 7949 39264451 312113120999