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31211313219937 is a prime number
BaseRepresentation
bin1110001100010111100110…
…01111001100100101100001
311002111202212002012222200101
413012023303033030211201
513042331232141014222
6150214140201222401
76400641303024604
oct706136317144541
9132452762188611
1031211313219937
119a437096a9794
123600b65791a01
1314552a27ca726
1479c8c81da33b
15391d27cc4927
hex1c62f33cc961

31211313219937 has 2 divisors, whose sum is σ = 31211313219938. Its totient is φ = 31211313219936.

The previous prime is 31211313219901. The next prime is 31211313220033. The reversal of 31211313219937 is 73991231311213.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 30514089889936 + 697223330001 = 5523956^2 + 834999^2 .

It is a cyclic number.

It is not a de Polignac number, because 31211313219937 - 239 = 30661557406049 is a prime.

It is not a weakly prime, because it can be changed into another prime (31211313217937) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15605656609968 + 15605656609969.

It is an arithmetic number, because the mean of its divisors is an integer number (15605656609969).

Almost surely, 231211313219937 is an apocalyptic number.

It is an amenable number.

31211313219937 is a deficient number, since it is larger than the sum of its proper divisors (1).

31211313219937 is an equidigital number, since it uses as much as digits as its factorization.

31211313219937 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 183708, while the sum is 46.

The spelling of 31211313219937 in words is "thirty-one trillion, two hundred eleven billion, three hundred thirteen million, two hundred nineteen thousand, nine hundred thirty-seven".