Base | Representation |
---|---|
bin | 100011011110111011001000… |
… | …1010001010001010000000110 |
3 | 1111221002202021120120222211020 |
4 | 1012331312101101101100012 |
5 | 311402131233402001304 |
6 | 3023450531305252010 |
7 | 122512310253616116 |
oct | 10675662121212006 |
9 | 1457082246528736 |
10 | 312113415656454 |
11 | 904a36133a3705 |
12 | 2b009807494006 |
13 | 10520226b39799 |
14 | 57105270bd046 |
15 | 2613bbd6735d9 |
hex | 11bdd91451406 |
312113415656454 has 16 divisors (see below), whose sum is σ = 628416273135600. Its totient is φ = 103339564915040.
The previous prime is 312113415656453. The next prime is 312113415656467. The reversal of 312113415656454 is 454656514311213.
It is a junction number, because it is equal to n+sod(n) for n = 312113415656397 and 312113415656406.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (312113415656453) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 174560074977 + ... + 174560076764.
It is an arithmetic number, because the mean of its divisors is an integer number (39276017070975).
Almost surely, 2312113415656454 is an apocalyptic number.
312113415656454 is an abundant number, since it is smaller than the sum of its proper divisors (316302857479146).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
312113415656454 is a wasteful number, since it uses less digits than its factorization.
312113415656454 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 349120151895.
The product of its digits is 5184000, while the sum is 51.
Adding to 312113415656454 its reverse (454656514311213), we get a palindrome (766769929967667).
The spelling of 312113415656454 in words is "three hundred twelve trillion, one hundred thirteen billion, four hundred fifteen million, six hundred fifty-six thousand, four hundred fifty-four".
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