Base | Representation |
---|---|
bin | 101101011010110011000… |
… | …111110001100001000011 |
3 | 102001101020102000220021221 |
4 | 231122303013301201003 |
5 | 402114104230311022 |
6 | 10345500454455511 |
7 | 441332020206424 |
oct | 55326307614103 |
9 | 12041212026257 |
10 | 3121151416387 |
11 | aa3744673a94 |
12 | 424a97364597 |
13 | 19842842ac34 |
14 | ab0c912364b |
15 | 562c5839cc7 |
hex | 2d6b31f1843 |
3121151416387 has 2 divisors, whose sum is σ = 3121151416388. Its totient is φ = 3121151416386.
The previous prime is 3121151416307. The next prime is 3121151416393. The reversal of 3121151416387 is 7836141511213.
3121151416387 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3121151416387 is a prime.
It is not a weakly prime, because it can be changed into another prime (3121151416307) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1560575708193 + 1560575708194.
It is an arithmetic number, because the mean of its divisors is an integer number (1560575708194).
Almost surely, 23121151416387 is an apocalyptic number.
3121151416387 is a deficient number, since it is larger than the sum of its proper divisors (1).
3121151416387 is an equidigital number, since it uses as much as digits as its factorization.
3121151416387 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 120960, while the sum is 43.
The spelling of 3121151416387 in words is "three trillion, one hundred twenty-one billion, one hundred fifty-one million, four hundred sixteen thousand, three hundred eighty-seven".
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