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312121000153 is a prime number
BaseRepresentation
bin1001000101010111101…
…11001000000011011001
31002211122020201122002201
410202223313020003121
520103210434001103
6355215244130201
731356435504244
oct4425367100331
91084566648081
10312121000153
111104081930a6
12505a8836961
132358207a651
141116cc5a25b
1581bb88151d
hex48abdc80d9

312121000153 has 2 divisors, whose sum is σ = 312121000154. Its totient is φ = 312121000152.

The previous prime is 312120999961. The next prime is 312121000157. The reversal of 312121000153 is 351000121213.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 289533314889 + 22587685264 = 538083^2 + 150292^2 .

It is a cyclic number.

It is not a de Polignac number, because 312121000153 - 225 = 312087445721 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 312121000153.

It is not a weakly prime, because it can be changed into another prime (312121000157) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156060500076 + 156060500077.

It is an arithmetic number, because the mean of its divisors is an integer number (156060500077).

Almost surely, 2312121000153 is an apocalyptic number.

It is an amenable number.

312121000153 is a deficient number, since it is larger than the sum of its proper divisors (1).

312121000153 is an equidigital number, since it uses as much as digits as its factorization.

312121000153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 180, while the sum is 19.

Adding to 312121000153 its reverse (351000121213), we get a palindrome (663121121366).

The spelling of 312121000153 in words is "three hundred twelve billion, one hundred twenty-one million, one hundred fifty-three", and thus it is an aban number.