Base | Representation |
---|---|
bin | 101101011010110111010… |
… | …001100110111000010011 |
3 | 102001101102021011100112011 |
4 | 231122313101212320103 |
5 | 402114230100244443 |
6 | 10345511424243351 |
7 | 441333524426644 |
oct | 55326721467023 |
9 | 12041367140464 |
10 | 3121221103123 |
11 | aa377aa40732 |
12 | 424ab6770557 |
13 | 1984399b9ca6 |
14 | ab0d44a36cb |
15 | 562cba02b9d |
hex | 2d6b7466e13 |
3121221103123 has 2 divisors, whose sum is σ = 3121221103124. Its totient is φ = 3121221103122.
The previous prime is 3121221103079. The next prime is 3121221103153. The reversal of 3121221103123 is 3213011221213.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3121221103123 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3121221103094 and 3121221103103.
It is not a weakly prime, because it can be changed into another prime (3121221103153) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1560610551561 + 1560610551562.
It is an arithmetic number, because the mean of its divisors is an integer number (1560610551562).
Almost surely, 23121221103123 is an apocalyptic number.
3121221103123 is a deficient number, since it is larger than the sum of its proper divisors (1).
3121221103123 is an equidigital number, since it uses as much as digits as its factorization.
3121221103123 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 3121221103123 its reverse (3213011221213), we get a palindrome (6334232324336).
The spelling of 3121221103123 in words is "three trillion, one hundred twenty-one billion, two hundred twenty-one million, one hundred three thousand, one hundred twenty-three".
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