Base | Representation |
---|---|
bin | 1110001100011001011111… |
… | …11010111010011111101001 |
3 | 11002111212111000221110222122 |
4 | 13012030233322322133221 |
5 | 13042340323304010004 |
6 | 150214425210401025 |
7 | 6401005444463411 |
oct | 706145772723751 |
9 | 132455430843878 |
10 | 31212331313129 |
11 | 9a4409136021a |
12 | 36011aa730175 |
13 | 1455405701135 |
14 | 79c9834d7641 |
15 | 391d8737bcbe |
hex | 1c632feba7e9 |
31212331313129 has 2 divisors, whose sum is σ = 31212331313130. Its totient is φ = 31212331313128.
The previous prime is 31212331313113. The next prime is 31212331313143. The reversal of 31212331313129 is 92131313321213.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 25242103319104 + 5970227994025 = 5024152^2 + 2443405^2 .
It is a cyclic number.
It is not a de Polignac number, because 31212331313129 - 24 = 31212331313113 is a prime.
It is not a weakly prime, because it can be changed into another prime (31212331313729) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15606165656564 + 15606165656565.
It is an arithmetic number, because the mean of its divisors is an integer number (15606165656565).
Almost surely, 231212331313129 is an apocalyptic number.
It is an amenable number.
31212331313129 is a deficient number, since it is larger than the sum of its proper divisors (1).
31212331313129 is an equidigital number, since it uses as much as digits as its factorization.
31212331313129 is an evil number, because the sum of its binary digits is even.
The product of its digits is 17496, while the sum is 35.
The spelling of 31212331313129 in words is "thirty-one trillion, two hundred twelve billion, three hundred thirty-one million, three hundred thirteen thousand, one hundred twenty-nine".
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