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312125445401201 is a prime number
BaseRepresentation
bin100011011111000000101111…
…0010011000110101001110001
31111221010220022221200100021222
41012332001132103012221301
5311402330403010314301
63023500241120354425
7122513214336016205
oct10676013623065161
91457126287610258
10312125445401201
11904a8726920a13
122b010004175a15
13105213c31b7043
145710d48a40b05
15261417481c31b
hex11be05e4c6a71

312125445401201 has 2 divisors, whose sum is σ = 312125445401202. Its totient is φ = 312125445401200.

The previous prime is 312125445401183. The next prime is 312125445401221. The reversal of 312125445401201 is 102104544521213.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 221130253461601 + 90995191939600 = 14870449^2 + 9539140^2 .

It is a cyclic number.

It is not a de Polignac number, because 312125445401201 - 210 = 312125445400177 is a prime.

It is not a weakly prime, because it can be changed into another prime (312125445401221) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156062722700600 + 156062722700601.

It is an arithmetic number, because the mean of its divisors is an integer number (156062722700601).

Almost surely, 2312125445401201 is an apocalyptic number.

It is an amenable number.

312125445401201 is a deficient number, since it is larger than the sum of its proper divisors (1).

312125445401201 is an equidigital number, since it uses as much as digits as its factorization.

312125445401201 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 38400, while the sum is 35.

Adding to 312125445401201 its reverse (102104544521213), we get a palindrome (414229989922414).

The spelling of 312125445401201 in words is "three hundred twelve trillion, one hundred twenty-five billion, four hundred forty-five million, four hundred one thousand, two hundred one".