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312131001331 is a prime number
BaseRepresentation
bin1001000101011000111…
…01010001101111110011
31002211122221112202010201
410202230131101233303
520103221014020311
6355220242340031
731356616510222
oct4425435215763
91084587482121
10312131001331
111104128a4136
12505b005a617
132358416c8c6
1411170300cb9
1581bc6a99c1
hex48ac751bf3

312131001331 has 2 divisors, whose sum is σ = 312131001332. Its totient is φ = 312131001330.

The previous prime is 312131001319. The next prime is 312131001359. The reversal of 312131001331 is 133100131213.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-312131001331 is a prime.

It is a super-2 number, since 2×3121310013312 (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 312131001299 and 312131001308.

It is not a weakly prime, because it can be changed into another prime (312131001311) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156065500665 + 156065500666.

It is an arithmetic number, because the mean of its divisors is an integer number (156065500666).

Almost surely, 2312131001331 is an apocalyptic number.

312131001331 is a deficient number, since it is larger than the sum of its proper divisors (1).

312131001331 is an equidigital number, since it uses as much as digits as its factorization.

312131001331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 312131001331 its reverse (133100131213), we get a palindrome (445231132544).

The spelling of 312131001331 in words is "three hundred twelve billion, one hundred thirty-one million, one thousand, three hundred thirty-one".