Base | Representation |
---|---|
bin | 1110001100011010111100… |
… | …10101100010011011110001 |
3 | 11002111221111022021010110121 |
4 | 13012031132111202123301 |
5 | 13042343422132410101 |
6 | 150215034345330241 |
7 | 6401033651545105 |
oct | 706153625423361 |
9 | 132457438233417 |
10 | 31213110044401 |
11 | 9a4445099458a |
12 | 3601387496981 |
13 | 14554cab4827c |
14 | 79ca18ac7905 |
15 | 391dd09020a1 |
hex | 1c635e5626f1 |
31213110044401 has 8 divisors (see below), whose sum is σ = 31979048137344. Its totient is φ = 30456236307840.
The previous prime is 31213110044387. The next prime is 31213110044477. The reversal of 31213110044401 is 10444001131213.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 31213110044401 - 27 = 31213110044273 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (31213110044201) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2266082125 + ... + 2266095898.
It is an arithmetic number, because the mean of its divisors is an integer number (3997381017168).
Almost surely, 231213110044401 is an apocalyptic number.
It is an amenable number.
31213110044401 is a deficient number, since it is larger than the sum of its proper divisors (765938092943).
31213110044401 is an equidigital number, since it uses as much as digits as its factorization.
31213110044401 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4532178191.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 31213110044401 its reverse (10444001131213), we get a palindrome (41657111175614).
The spelling of 31213110044401 in words is "thirty-one trillion, two hundred thirteen billion, one hundred ten million, forty-four thousand, four hundred one".
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