Base | Representation |
---|---|
bin | 100011011111000011110101… |
… | …1001100000110100001010011 |
3 | 1111221011112112000020022211200 |
4 | 1012332013223030012201103 |
5 | 311402433022123323103 |
6 | 3023503301544042243 |
7 | 122513541342134550 |
oct | 10676075314064123 |
9 | 1457145460208750 |
10 | 312132104120403 |
11 | 90500533566236 |
12 | 2b011362163383 |
13 | 10521c1489a688 |
14 | 57113bb11da27 |
15 | 26144141c10a3 |
hex | 11be1eb306853 |
312132104120403 has 48 divisors (see below), whose sum is σ = 519204418816512. Its totient is φ = 176997826512000.
The previous prime is 312132104120371. The next prime is 312132104120423. The reversal of 312132104120403 is 304021401231213.
312132104120403 is a `hidden beast` number, since 3 + 1 + 2 + 1 + 3 + 210 + 41 + 2 + 0 + 403 = 666.
It is not a de Polignac number, because 312132104120403 - 25 = 312132104120371 is a prime.
It is not an unprimeable number, because it can be changed into a prime (312132104120423) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 1385656863 + ... + 1385882103.
It is an arithmetic number, because the mean of its divisors is an integer number (10816758725344).
Almost surely, 2312132104120403 is an apocalyptic number.
312132104120403 is a deficient number, since it is larger than the sum of its proper divisors (207072314696109).
312132104120403 is a wasteful number, since it uses less digits than its factorization.
312132104120403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 393296 (or 393293 counting only the distinct ones).
The product of its (nonzero) digits is 3456, while the sum is 27.
Adding to 312132104120403 its reverse (304021401231213), we get a palindrome (616153505351616).
The spelling of 312132104120403 in words is "three hundred twelve trillion, one hundred thirty-two billion, one hundred four million, one hundred twenty thousand, four hundred three".
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