Base | Representation |
---|---|
bin | 11101000100011100… |
… | …111111000100011011 |
3 | 2222120022011212111202 |
4 | 131010130333010123 |
5 | 1002411041020443 |
6 | 22201131344415 |
7 | 2153330664521 |
oct | 350434770433 |
9 | 88508155452 |
10 | 31213220123 |
11 | 1226805a298 |
12 | 60712b210b |
13 | 2c35837a27 |
14 | 172161a311 |
15 | c2a3c67b8 |
hex | 74473f11b |
31213220123 has 2 divisors, whose sum is σ = 31213220124. Its totient is φ = 31213220122.
The previous prime is 31213220099. The next prime is 31213220161. The reversal of 31213220123 is 32102231213.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 31213220123 - 216 = 31213154587 is a prime.
It is a super-2 number, since 2×312132201232 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 31213220095 and 31213220104.
It is not a weakly prime, because it can be changed into another prime (31213220183) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15606610061 + 15606610062.
It is an arithmetic number, because the mean of its divisors is an integer number (15606610062).
Almost surely, 231213220123 is an apocalyptic number.
31213220123 is a deficient number, since it is larger than the sum of its proper divisors (1).
31213220123 is an equidigital number, since it uses as much as digits as its factorization.
31213220123 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 31213220123 its reverse (32102231213), we get a palindrome (63315451336).
The spelling of 31213220123 in words is "thirty-one billion, two hundred thirteen million, two hundred twenty thousand, one hundred twenty-three".
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