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312134121075577 is a prime number
BaseRepresentation
bin100011011111000100110001…
…1011010001011001101111001
31111221011201201120111021012011
41012332021203122023031321
5311403001134443404302
63023504234034245521
7122513642333024413
oct10676114332131571
91457151646437164
10312134121075577
1190501379033539
122b0118257268a1
1310522176700288
14571152cd4d9b3
1526144d12d25d7
hex11be26368b379

312134121075577 has 2 divisors, whose sum is σ = 312134121075578. Its totient is φ = 312134121075576.

The previous prime is 312134121075461. The next prime is 312134121075631. The reversal of 312134121075577 is 775570121431213.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 196435249367296 + 115698871708281 = 14015536^2 + 10756341^2 .

It is a cyclic number.

It is not a de Polignac number, because 312134121075577 - 211 = 312134121073529 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 312134121075577.

It is not a weakly prime, because it can be changed into another prime (312134121072577) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156067060537788 + 156067060537789.

It is an arithmetic number, because the mean of its divisors is an integer number (156067060537789).

Almost surely, 2312134121075577 is an apocalyptic number.

It is an amenable number.

312134121075577 is a deficient number, since it is larger than the sum of its proper divisors (1).

312134121075577 is an equidigital number, since it uses as much as digits as its factorization.

312134121075577 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1234800, while the sum is 49.

The spelling of 312134121075577 in words is "three hundred twelve trillion, one hundred thirty-four billion, one hundred twenty-one million, seventy-five thousand, five hundred seventy-seven".