3121343431 has 4 divisors (see below), whose sum is σ = 3125746600. Its totient is φ = 3116940264.

The previous prime is 3121343413. The next prime is 3121343437. The reversal of 3121343431 is 1343431213.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 1343431213 = 109 ⋅12325057.

It is a cyclic number.

It is not a de Polignac number, because 3121343431 - 2¹¹ = 3121341383 is a prime.

It is a super-2 number, since 2×3121343431² = 19485569628493703522, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3121343396 and 3121343405.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3121343437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2200521 + ... + 2201938.

It is an arithmetic number, because the mean of its divisors is an integer number (781436650).

Almost surely, 2^3121343431 is an apocalyptic number.

3121343431 is a deficient number, since it is larger than the sum of its proper divisors (4403169).

3121343431 is an equidigital number, since it uses as much as digits as its factorization.

3121343431 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4403168.

The product of its digits is 2592, while the sum is 25.

The square root of 3121343431 is about 55868.9845173509. The cubic root of 3121343431 is about 1461.4384133451.

Adding to 3121343431 its reverse (1343431213), we get a palindrome (4464774644).

The spelling of 3121343431 in words is "three billion, one hundred twenty-one million, three hundred forty-three thousand, four hundred thirty-one".