Base | Representation |
---|---|
bin | 1110001100011011110000… |
… | …01010010101011010100010 |
3 | 11002111222121111112120010202 |
4 | 13012031320022111122202 |
5 | 13042400314042040411 |
6 | 150215145344025202 |
7 | 6401050462360025 |
oct | 706157012253242 |
9 | 132458544476122 |
10 | 31213543315106 |
11 | 9a44653514249 |
12 | 3601488602202 |
13 | 1455569838479 |
14 | 79ca5a46d1bc |
15 | 391e0898883b |
hex | 1c63782956a2 |
31213543315106 has 4 divisors (see below), whose sum is σ = 46820314972662. Its totient is φ = 15606771657552.
The previous prime is 31213543315103. The next prime is 31213543315109. The reversal of 31213543315106 is 60151334531213.
It is a semiprime because it is the product of two primes.
It is an interprime number because it is at equal distance from previous prime (31213543315103) and next prime (31213543315109).
It can be written as a sum of positive squares in only one way, i.e., 30192552300625 + 1020991014481 = 5494775^2 + 1010441^2 .
It is a self number, because there is not a number n which added to its sum of digits gives 31213543315106.
It is not an unprimeable number, because it can be changed into a prime (31213543315103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7803385828775 + ... + 7803385828778.
Almost surely, 231213543315106 is an apocalyptic number.
31213543315106 is a deficient number, since it is larger than the sum of its proper divisors (15606771657556).
31213543315106 is a wasteful number, since it uses less digits than its factorization.
31213543315106 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 15606771657555.
The product of its (nonzero) digits is 97200, while the sum is 38.
Adding to 31213543315106 its reverse (60151334531213), we get a palindrome (91364877846319).
The spelling of 31213543315106 in words is "thirty-one trillion, two hundred thirteen billion, five hundred forty-three million, three hundred fifteen thousand, one hundred six".
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