Base | Representation |
---|---|
bin | 101101011010111111101… |
… | …000110110100000000011 |
3 | 102001101210001011220001202 |
4 | 231122333220312200003 |
5 | 402120022010223042 |
6 | 10345533355451415 |
7 | 441340150153664 |
oct | 55327750664003 |
9 | 12041701156052 |
10 | 3121361414147 |
11 | aa3842165459 |
12 | 424b35756b6b |
13 | 19845caa5a72 |
14 | ab108d8936b |
15 | 562d8ebb632 |
hex | 2d6bfa36803 |
3121361414147 has 16 divisors (see below), whose sum is σ = 3258207912960. Its totient is φ = 2988045994752.
The previous prime is 3121361414117. The next prime is 3121361414173. The reversal of 3121361414147 is 7414141631213.
It is a cyclic number.
It is not a de Polignac number, because 3121361414147 - 218 = 3121361152003 is a prime.
It is a super-3 number, since 3×31213614141473 (a number of 38 digits) contains 333 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 3121361414147.
It is not an unprimeable number, because it can be changed into a prime (3121361414117) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3203147 + ... + 4062372.
It is an arithmetic number, because the mean of its divisors is an integer number (203637994560).
Almost surely, 23121361414147 is an apocalyptic number.
3121361414147 is a deficient number, since it is larger than the sum of its proper divisors (136846498813).
3121361414147 is a wasteful number, since it uses less digits than its factorization.
3121361414147 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7265762.
The product of its digits is 48384, while the sum is 38.
The spelling of 3121361414147 in words is "three trillion, one hundred twenty-one billion, three hundred sixty-one million, four hundred fourteen thousand, one hundred forty-seven".
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