Base | Representation |
---|---|
bin | 100011011111001000000010… |
… | …1010100010000111100001011 |
3 | 1111221012101211012112120111222 |
4 | 1012332100011110100330023 |
5 | 311403110014343334233 |
6 | 3023511353455312255 |
7 | 122514311150230541 |
oct | 10676200524207413 |
9 | 1457171735476458 |
10 | 312141132402443 |
11 | 90504346814153 |
12 | 2b01306181b68b |
13 | 10522a231709b6 |
14 | 57119d61b7d91 |
15 | 2614791ad7898 |
hex | 11be405510f0b |
312141132402443 has 2 divisors, whose sum is σ = 312141132402444. Its totient is φ = 312141132402442.
The previous prime is 312141132402413. The next prime is 312141132402503. The reversal of 312141132402443 is 344204231141213.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 312141132402443 - 210 = 312141132401419 is a prime.
It is not a weakly prime, because it can be changed into another prime (312141132402413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156070566201221 + 156070566201222.
It is an arithmetic number, because the mean of its divisors is an integer number (156070566201222).
Almost surely, 2312141132402443 is an apocalyptic number.
312141132402443 is a deficient number, since it is larger than the sum of its proper divisors (1).
312141132402443 is an equidigital number, since it uses as much as digits as its factorization.
312141132402443 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 55296, while the sum is 35.
Adding to 312141132402443 its reverse (344204231141213), we get a palindrome (656345363543656).
The spelling of 312141132402443 in words is "three hundred twelve trillion, one hundred forty-one billion, one hundred thirty-two million, four hundred two thousand, four hundred forty-three".
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