Base | Representation |
---|---|
bin | 101101011011000011001… |
… | …000011101100011111011 |
3 | 102001101221010110222222122 |
4 | 231123003020131203323 |
5 | 402120132012013001 |
6 | 10345543252111455 |
7 | 441341461334153 |
oct | 55330310354373 |
9 | 12041833428878 |
10 | 3121420032251 |
11 | aa3872262074 |
12 | 424b5130558b |
13 | 19846bc8aa31 |
14 | ab112a87763 |
15 | 562de1e9b1b |
hex | 2d6c321d8fb |
3121420032251 has 2 divisors, whose sum is σ = 3121420032252. Its totient is φ = 3121420032250.
The previous prime is 3121420032233. The next prime is 3121420032329. The reversal of 3121420032251 is 1522300241213.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3121420032251 - 238 = 2846542125307 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 3121420032251.
It is not a weakly prime, because it can be changed into another prime (3121420038251) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1560710016125 + 1560710016126.
It is an arithmetic number, because the mean of its divisors is an integer number (1560710016126).
Almost surely, 23121420032251 is an apocalyptic number.
3121420032251 is a deficient number, since it is larger than the sum of its proper divisors (1).
3121420032251 is an equidigital number, since it uses as much as digits as its factorization.
3121420032251 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2880, while the sum is 26.
Adding to 3121420032251 its reverse (1522300241213), we get a palindrome (4643720273464).
The spelling of 3121420032251 in words is "three trillion, one hundred twenty-one billion, four hundred twenty million, thirty-two thousand, two hundred fifty-one".
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