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3121440219977 is a prime number
BaseRepresentation
bin101101011011000100010…
…101011110001101001001
3102001101222112110122100012
4231123010111132031021
5402120202144014402
610345545252521305
7441342125044412
oct55330425361511
912041875418305
103121440219977
11aa38826a0442
12424b58020235
13198473208731
14ab115620809
15562e0d86452
hex2d6c455e349

3121440219977 has 2 divisors, whose sum is σ = 3121440219978. Its totient is φ = 3121440219976.

The previous prime is 3121440219943. The next prime is 3121440219991. The reversal of 3121440219977 is 7799120441213.

3121440219977 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3025474093321 + 95966126656 = 1739389^2 + 309784^2 .

It is an emirp because it is prime and its reverse (7799120441213) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 3121440219977 - 230 = 3120366478153 is a prime.

It is not a weakly prime, because it can be changed into another prime (3121440219077) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1560720109988 + 1560720109989.

It is an arithmetic number, because the mean of its divisors is an integer number (1560720109989).

Almost surely, 23121440219977 is an apocalyptic number.

It is an amenable number.

3121440219977 is a deficient number, since it is larger than the sum of its proper divisors (1).

3121440219977 is an equidigital number, since it uses as much as digits as its factorization.

3121440219977 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 762048, while the sum is 50.

The spelling of 3121440219977 in words is "three trillion, one hundred twenty-one billion, four hundred forty million, two hundred nineteen thousand, nine hundred seventy-seven".