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31214483 is a prime number
BaseRepresentation
bin111011100010…
…0101110010011
32011201212012222
41313010232103
530442330413
63033011255
7526214216
oct167045623
964655188
1031214483
111668a9a3
12a553b2b
13660ba11
14420777d
152b18b08
hex1dc4b93

31214483 has 2 divisors, whose sum is σ = 31214484. Its totient is φ = 31214482.

The previous prime is 31214461. The next prime is 31214497. The reversal of 31214483 is 38441213.

It is a strong prime.

It is an emirp because it is prime and its reverse (38441213) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 31214483 - 26 = 31214419 is a prime.

It is a Chen prime.

It is equal to p1928330 and since 31214483 and 1928330 have the same sum of digits, it is a Honaker prime.

It is not a weakly prime, because it can be changed into another prime (31214423) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15607241 + 15607242.

It is an arithmetic number, because the mean of its divisors is an integer number (15607242).

Almost surely, 231214483 is an apocalyptic number.

31214483 is a deficient number, since it is larger than the sum of its proper divisors (1).

31214483 is an equidigital number, since it uses as much as digits as its factorization.

31214483 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2304, while the sum is 26.

The square root of 31214483 is about 5586.9923035565. The cubic root of 31214483 is about 314.8608875949.

Adding to 31214483 its reverse (38441213), we get a palindrome (69655696).

The spelling of 31214483 in words is "thirty-one million, two hundred fourteen thousand, four hundred eighty-three".