Base | Representation |
---|---|
bin | 11101000100111000… |
… | …100000000001101001 |
3 | 2222120210202022201101 |
4 | 131010320200001221 |
5 | 1002414412324001 |
6 | 22201550121401 |
7 | 2153446205362 |
oct | 350470400151 |
9 | 88523668641 |
10 | 31220433001 |
11 | 1227113644a |
12 | 60737b0261 |
13 | 2c37191ac4 |
14 | 1722576b69 |
15 | c2ad4da01 |
hex | 744e20069 |
31220433001 has 2 divisors, whose sum is σ = 31220433002. Its totient is φ = 31220433000.
The previous prime is 31220432981. The next prime is 31220433031. The reversal of 31220433001 is 10033402213.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 19147917376 + 12072515625 = 138376^2 + 109875^2 .
It is a cyclic number.
It is not a de Polignac number, because 31220433001 - 211 = 31220430953 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 31220433001.
It is not a weakly prime, because it can be changed into another prime (31220433031) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15610216500 + 15610216501.
It is an arithmetic number, because the mean of its divisors is an integer number (15610216501).
Almost surely, 231220433001 is an apocalyptic number.
It is an amenable number.
31220433001 is a deficient number, since it is larger than the sum of its proper divisors (1).
31220433001 is an equidigital number, since it uses as much as digits as its factorization.
31220433001 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 19.
Adding to 31220433001 its reverse (10033402213), we get a palindrome (41253835214).
The spelling of 31220433001 in words is "thirty-one billion, two hundred twenty million, four hundred thirty-three thousand, one".
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