Base | Representation |
---|---|
bin | 101101011011101011111… |
… | …011101101100000100001 |
3 | 102001110200211112101102112 |
4 | 231123223323231200201 |
5 | 402123032231234203 |
6 | 10350135223525105 |
7 | 441364442566004 |
oct | 55335373554041 |
9 | 12043624471375 |
10 | 3122104555553 |
11 | aa40936a0605 |
12 | 4251025b9795 |
13 | 19854aa3b7c9 |
14 | ab17995353b |
15 | 5632e3616d8 |
hex | 2d6ebeed821 |
3122104555553 has 2 divisors, whose sum is σ = 3122104555554. Its totient is φ = 3122104555552.
The previous prime is 3122104555523. The next prime is 3122104555651. The reversal of 3122104555553 is 3555554012213.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2647558545424 + 474546010129 = 1627132^2 + 688873^2 .
It is a cyclic number.
It is not a de Polignac number, because 3122104555553 - 210 = 3122104554529 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 3122104555553.
It is not a weakly prime, because it can be changed into another prime (3122104555513) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1561052277776 + 1561052277777.
It is an arithmetic number, because the mean of its divisors is an integer number (1561052277777).
Almost surely, 23122104555553 is an apocalyptic number.
It is an amenable number.
3122104555553 is a deficient number, since it is larger than the sum of its proper divisors (1).
3122104555553 is an equidigital number, since it uses as much as digits as its factorization.
3122104555553 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 450000, while the sum is 41.
Adding to 3122104555553 its reverse (3555554012213), we get a palindrome (6677658567766).
The spelling of 3122104555553 in words is "three trillion, one hundred twenty-two billion, one hundred four million, five hundred fifty-five thousand, five hundred fifty-three".
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