Base | Representation |
---|---|
bin | 101101011011101100010… |
… | …101100011011011010011 |
3 | 102001110201022021120020002 |
4 | 231123230111203123103 |
5 | 402123041000030003 |
6 | 10350140025040215 |
7 | 441364554302411 |
oct | 55335425433323 |
9 | 12043638246202 |
10 | 3122111330003 |
11 | aa40974a8326 |
12 | 42510492606b |
13 | 19854c271163 |
14 | ab17a7d82b1 |
15 | 5632ec4da88 |
hex | 2d6ec5636d3 |
3122111330003 has 2 divisors, whose sum is σ = 3122111330004. Its totient is φ = 3122111330002.
The previous prime is 3122111329937. The next prime is 3122111330021. The reversal of 3122111330003 is 3000331112213.
It is a strong prime.
It is an emirp because it is prime and its reverse (3000331112213) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 3122111330003 - 214 = 3122111313619 is a prime.
It is not a weakly prime, because it can be changed into another prime (3122111332003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1561055665001 + 1561055665002.
It is an arithmetic number, because the mean of its divisors is an integer number (1561055665002).
Almost surely, 23122111330003 is an apocalyptic number.
3122111330003 is a deficient number, since it is larger than the sum of its proper divisors (1).
3122111330003 is an equidigital number, since it uses as much as digits as its factorization.
3122111330003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 20.
Adding to 3122111330003 its reverse (3000331112213), we get a palindrome (6122442442216).
The spelling of 3122111330003 in words is "three trillion, one hundred twenty-two billion, one hundred eleven million, three hundred thirty thousand, three".
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