Base | Representation |
---|---|
bin | 11101000100111011… |
… | …100101011001011001 |
3 | 2222120212021101200022 |
4 | 131010323211121121 |
5 | 1002420114211213 |
6 | 22202015320225 |
7 | 2153456113334 |
oct | 350473453131 |
9 | 88525241608 |
10 | 31221241433 |
11 | 12271638878 |
12 | 6073b20075 |
13 | 2c373b5a75 |
14 | 172270761b |
15 | c2ae5d308 |
hex | 744ee5659 |
31221241433 has 2 divisors, whose sum is σ = 31221241434. Its totient is φ = 31221241432.
The previous prime is 31221241367. The next prime is 31221241487. The reversal of 31221241433 is 33414212213.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 29423227024 + 1798014409 = 171532^2 + 42403^2 .
It is a cyclic number.
It is not a de Polignac number, because 31221241433 - 212 = 31221237337 is a prime.
It is not a weakly prime, because it can be changed into another prime (31221241133) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15610620716 + 15610620717.
It is an arithmetic number, because the mean of its divisors is an integer number (15610620717).
Almost surely, 231221241433 is an apocalyptic number.
It is an amenable number.
31221241433 is a deficient number, since it is larger than the sum of its proper divisors (1).
31221241433 is an equidigital number, since it uses as much as digits as its factorization.
31221241433 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 3456, while the sum is 26.
Adding to 31221241433 its reverse (33414212213), we get a palindrome (64635453646).
The spelling of 31221241433 in words is "thirty-one billion, two hundred twenty-one million, two hundred forty-one thousand, four hundred thirty-three".
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