Base | Representation |
---|---|
bin | 100011011111101001101100… |
… | …1000011000010110000000011 |
3 | 1111221110022100221112221210022 |
4 | 1012333103121003002300003 |
5 | 311410301022424300103 |
6 | 3024004505141324055 |
7 | 122522450130635462 |
oct | 10677233103026003 |
9 | 1457408327487708 |
10 | 312213404134403 |
11 | 90531a6327a052 |
12 | 2b02507140662b |
13 | 105297a0143935 |
14 | 57152d07c09d9 |
15 | 26165c1884138 |
hex | 11bf4d90c2c03 |
312213404134403 has 2 divisors, whose sum is σ = 312213404134404. Its totient is φ = 312213404134402.
The previous prime is 312213404134393. The next prime is 312213404134481. The reversal of 312213404134403 is 304431404312213.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-312213404134403 is a prime.
It is not a weakly prime, because it can be changed into another prime (312213404194403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156106702067201 + 156106702067202.
It is an arithmetic number, because the mean of its divisors is an integer number (156106702067202).
Almost surely, 2312213404134403 is an apocalyptic number.
312213404134403 is a deficient number, since it is larger than the sum of its proper divisors (1).
312213404134403 is an equidigital number, since it uses as much as digits as its factorization.
312213404134403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 82944, while the sum is 35.
Adding to 312213404134403 its reverse (304431404312213), we get a palindrome (616644808446616).
The spelling of 312213404134403 in words is "three hundred twelve trillion, two hundred thirteen billion, four hundred four million, one hundred thirty-four thousand, four hundred three".
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