Base | Representation |
---|---|
bin | 1110001100101101101111… |
… | …10000001010101110001011 |
3 | 11002112220112111112200111221 |
4 | 13012112313300022232023 |
5 | 13043030103213210404 |
6 | 150223423511102511 |
7 | 6401542002066052 |
oct | 706266760125613 |
9 | 132486474480457 |
10 | 31223200131979 |
11 | 9a4875953a739 |
12 | 3603322671a37 |
13 | 14564483b84ab |
14 | 79d2d4bbb399 |
15 | 3922c1657954 |
hex | 1c65b7c0ab8b |
31223200131979 has 2 divisors, whose sum is σ = 31223200131980. Its totient is φ = 31223200131978.
The previous prime is 31223200131881. The next prime is 31223200131997. The reversal of 31223200131979 is 97913100232213.
Together with next prime (31223200131997) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 31223200131979 - 215 = 31223200099211 is a prime.
It is a super-2 number, since 2×312232001319792 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (31223200135979) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15611600065989 + 15611600065990.
It is an arithmetic number, because the mean of its divisors is an integer number (15611600065990).
Almost surely, 231223200131979 is an apocalyptic number.
31223200131979 is a deficient number, since it is larger than the sum of its proper divisors (1).
31223200131979 is an equidigital number, since it uses as much as digits as its factorization.
31223200131979 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 122472, while the sum is 43.
The spelling of 31223200131979 in words is "thirty-one trillion, two hundred twenty-three billion, two hundred million, one hundred thirty-one thousand, nine hundred seventy-nine".
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