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312234140004131 is a prime number
BaseRepresentation
bin100011011111110011010110…
…1000000000110111100100011
31111221112021220001202021112102
41012333212231000012330203
5311411121004320113011
63024022214515121015
7122524113026630252
oct10677465500067443
91457467801667472
10312234140004131
119053a834117974
122b0290998a316b
131052b726109537
1457162da6da799
152616dd700a73b
hex11bf9ad006f23

312234140004131 has 2 divisors, whose sum is σ = 312234140004132. Its totient is φ = 312234140004130.

The previous prime is 312234140004037. The next prime is 312234140004239. The reversal of 312234140004131 is 131400041432213.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-312234140004131 is a prime.

It is a super-2 number, since 2×3122341400041312 (a number of 30 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 312234140004094 and 312234140004103.

It is not a weakly prime, because it can be changed into another prime (312234140204131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156117070002065 + 156117070002066.

It is an arithmetic number, because the mean of its divisors is an integer number (156117070002066).

Almost surely, 2312234140004131 is an apocalyptic number.

312234140004131 is a deficient number, since it is larger than the sum of its proper divisors (1).

312234140004131 is an equidigital number, since it uses as much as digits as its factorization.

312234140004131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 312234140004131 its reverse (131400041432213), we get a palindrome (443634181436344).

The spelling of 312234140004131 in words is "three hundred twelve trillion, two hundred thirty-four billion, one hundred forty million, four thousand, one hundred thirty-one".