Base | Representation |
---|---|
bin | 101101011011111101100… |
… | …111110111101110010001 |
3 | 102001111110111222211012002 |
4 | 231123331213313232101 |
5 | 402124134221010101 |
6 | 10350224505043345 |
7 | 441405005342423 |
oct | 55337547675621 |
9 | 12044414884162 |
10 | 3122401344401 |
11 | aa4226181449 |
12 | 425185a86555 |
13 | 198597383b01 |
14 | ab1a712c813 |
15 | 5634a438d6b |
hex | 2d6fd9f7b91 |
3122401344401 has 2 divisors, whose sum is σ = 3122401344402. Its totient is φ = 3122401344400.
The previous prime is 3122401344367. The next prime is 3122401344443. The reversal of 3122401344401 is 1044431042213.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3054801344401 + 67600000000 = 1747799^2 + 260000^2 .
It is a cyclic number.
It is not a de Polignac number, because 3122401344401 - 234 = 3105221475217 is a prime.
It is not a weakly prime, because it can be changed into another prime (3122401344451) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1561200672200 + 1561200672201.
It is an arithmetic number, because the mean of its divisors is an integer number (1561200672201).
Almost surely, 23122401344401 is an apocalyptic number.
It is an amenable number.
3122401344401 is a deficient number, since it is larger than the sum of its proper divisors (1).
3122401344401 is an equidigital number, since it uses as much as digits as its factorization.
3122401344401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9216, while the sum is 29.
Adding to 3122401344401 its reverse (1044431042213), we get a palindrome (4166832386614).
The spelling of 3122401344401 in words is "three trillion, one hundred twenty-two billion, four hundred one million, three hundred forty-four thousand, four hundred one".
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