Base | Representation |
---|---|
bin | 1110001100101111011011… |
… | …11111001001110100111111 |
3 | 11002112222212220200022010221 |
4 | 13012113231333021310333 |
5 | 13043033434131431033 |
6 | 150224054053242211 |
7 | 6401603361101302 |
oct | 706275577116477 |
9 | 132488786608127 |
10 | 31224110030143 |
11 | 9a49086112698 |
12 | 3603537333367 |
13 | 1456561a69284 |
14 | 79d37d992b39 |
15 | 39232648c12d |
hex | 1c65edfc9d3f |
31224110030143 has 4 divisors (see below), whose sum is σ = 31224121294408. Its totient is φ = 31224098765880.
The previous prime is 31224110030027. The next prime is 31224110030161. The reversal of 31224110030143 is 34103001142213.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is not a de Polignac number, because 31224110030143 - 217 = 31224109899071 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (31224110037143) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1758805 + ... + 8095777.
It is an arithmetic number, because the mean of its divisors is an integer number (7806030323602).
Almost surely, 231224110030143 is an apocalyptic number.
31224110030143 is a deficient number, since it is larger than the sum of its proper divisors (11264265).
31224110030143 is an equidigital number, since it uses as much as digits as its factorization.
31224110030143 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11264264.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 31224110030143 its reverse (34103001142213), we get a palindrome (65327111172356).
The spelling of 31224110030143 in words is "thirty-one trillion, two hundred twenty-four billion, one hundred ten million, thirty thousand, one hundred forty-three".
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