Base | Representation |
---|---|
bin | 100011011111110111111101… |
… | …0000101001101010011101011 |
3 | 1111221120020101211120122022210 |
4 | 1012333233322011031103223 |
5 | 311411301224404334011 |
6 | 3024030531324420203 |
7 | 122524612655012403 |
oct | 10677577205152353 |
9 | 1457506354518283 |
10 | 312244023121131 |
11 | 90543a45959a62 |
12 | 2b02ab976a7663 |
13 | 1052c63c82176a |
14 | 5716997115803 |
15 | 26172b49cb6a6 |
hex | 11bfbfa14d4eb |
312244023121131 has 32 divisors (see below), whose sum is σ = 431035992414720. Its totient is φ = 200819207635200.
The previous prime is 312244023121067. The next prime is 312244023121153. The reversal of 312244023121131 is 131121320442213.
It is not a de Polignac number, because 312244023121131 - 26 = 312244023121067 is a prime.
It is a super-2 number, since 2×3122440231211312 (a number of 30 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (312244023121171) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1911269256 + ... + 1911432618.
It is an arithmetic number, because the mean of its divisors is an integer number (13469874762960).
Almost surely, 2312244023121131 is an apocalyptic number.
312244023121131 is a deficient number, since it is larger than the sum of its proper divisors (118791969293589).
312244023121131 is a wasteful number, since it uses less digits than its factorization.
312244023121131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 181347.
The product of its (nonzero) digits is 6912, while the sum is 30.
Adding to 312244023121131 its reverse (131121320442213), we get a palindrome (443365343563344).
The spelling of 312244023121131 in words is "three hundred twelve trillion, two hundred forty-four billion, twenty-three million, one hundred twenty-one thousand, one hundred thirty-one".
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