Base | Representation |
---|---|
bin | 100011100000011011110011… |
… | …0100001001110000011010111 |
3 | 1111221211121002210022022002010 |
4 | 1013000313212201032003113 |
5 | 311414031404102044343 |
6 | 3024130142203115303 |
7 | 122533306432342266 |
oct | 10700674641160327 |
9 | 1457747083268063 |
10 | 312321004331223 |
11 | 90573659831548 |
12 | 2b041aa0512b33 |
13 | 1053698a3c3654 |
14 | 571a5bad965dd |
15 | 26192bce43d33 |
hex | 11c0de684e0d7 |
312321004331223 has 16 divisors (see below), whose sum is σ = 423712450137600. Its totient is φ = 204575553082560.
The previous prime is 312321004331209. The next prime is 312321004331227. The reversal of 312321004331223 is 322133400123213.
It is not a de Polignac number, because 312321004331223 - 24 = 312321004331207 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (312321004331227) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 471214918 + ... + 471877251.
It is an arithmetic number, because the mean of its divisors is an integer number (26482028133600).
Almost surely, 2312321004331223 is an apocalyptic number.
312321004331223 is a deficient number, since it is larger than the sum of its proper divisors (111391445806377).
312321004331223 is a wasteful number, since it uses less digits than its factorization.
312321004331223 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 943094102.
The product of its (nonzero) digits is 15552, while the sum is 30.
Adding to 312321004331223 its reverse (322133400123213), we get a palindrome (634454404454436).
The spelling of 312321004331223 in words is "three hundred twelve trillion, three hundred twenty-one billion, four million, three hundred thirty-one thousand, two hundred twenty-three".
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