Base | Representation |
---|---|
bin | 100011100000011100010100… |
… | …0100000000101011011010001 |
3 | 1111221211200221221022122220212 |
4 | 1013000320220200011123101 |
5 | 311414041141000030001 |
6 | 3024130444110013505 |
7 | 122533346033565053 |
oct | 10700705040053321 |
9 | 1457750857278825 |
10 | 312322111330001 |
11 | 90574077697073 |
12 | 2b04214b1a7295 |
13 | 10536b05854b06 |
14 | 571a683dd78d3 |
15 | 261933520d7bb |
hex | 11c0e288056d1 |
312322111330001 has 2 divisors, whose sum is σ = 312322111330002. Its totient is φ = 312322111330000.
The previous prime is 312322111329989. The next prime is 312322111330027. The reversal of 312322111330001 is 100033111223213.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 308166649464976 + 4155461865025 = 17554676^2 + 2038495^2 .
It is a cyclic number.
It is not a de Polignac number, because 312322111330001 - 210 = 312322111328977 is a prime.
It is not a weakly prime, because it can be changed into another prime (312322111380001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156161055665000 + 156161055665001.
It is an arithmetic number, because the mean of its divisors is an integer number (156161055665001).
Almost surely, 2312322111330001 is an apocalyptic number.
It is an amenable number.
312322111330001 is a deficient number, since it is larger than the sum of its proper divisors (1).
312322111330001 is an equidigital number, since it uses as much as digits as its factorization.
312322111330001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 312322111330001 its reverse (100033111223213), we get a palindrome (412355222553214).
The spelling of 312322111330001 in words is "three hundred twelve trillion, three hundred twenty-two billion, one hundred eleven million, three hundred thirty thousand, one".
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