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312334021132361 is a prime number
BaseRepresentation
bin100011100000100001110111…
…0011000011000000001001001
31111221212211200221201022100222
41013001003232120120001021
5311414240033402213421
63024140133554235425
7122534250131333654
oct10701035630300111
91457784627638328
10312334021132361
1190579129441938
122b044513885b75
1310537c830c8747
14571b093a5689b
1526197d0ab3cab
hex11c10ee618049

312334021132361 has 2 divisors, whose sum is σ = 312334021132362. Its totient is φ = 312334021132360.

The previous prime is 312334021132303. The next prime is 312334021132403. The reversal of 312334021132361 is 163231120433213.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 204105682341136 + 108228338791225 = 14286556^2 + 10403285^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-312334021132361 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (312334021132561) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156167010566180 + 156167010566181.

It is an arithmetic number, because the mean of its divisors is an integer number (156167010566181).

Almost surely, 2312334021132361 is an apocalyptic number.

It is an amenable number.

312334021132361 is a deficient number, since it is larger than the sum of its proper divisors (1).

312334021132361 is an equidigital number, since it uses as much as digits as its factorization.

312334021132361 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 46656, while the sum is 35.

Adding to 312334021132361 its reverse (163231120433213), we get a palindrome (475565141565574).

The spelling of 312334021132361 in words is "three hundred twelve trillion, three hundred thirty-four billion, twenty-one million, one hundred thirty-two thousand, three hundred sixty-one".