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312334301404049 is a prime number
BaseRepresentation
bin100011100000100001111111…
…1000101100001101110010001
31111221212212102111002120211212
41013001003333011201232101
5311414241122124412144
63024140221445345505
7122534260103525411
oct10701037705415621
91457785374076755
10312334301404049
1190579262671131
122b044591708295
1310537cc91a9992
14571b0bcd72641
1526197ea4c749e
hex11c10ff161b91

312334301404049 has 2 divisors, whose sum is σ = 312334301404050. Its totient is φ = 312334301404048.

The previous prime is 312334301404043. The next prime is 312334301404183. The reversal of 312334301404049 is 940404103433213.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 297195533209600 + 15138768194449 = 17239360^2 + 3890857^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-312334301404049 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 312334301403997 and 312334301404015.

It is not a weakly prime, because it can be changed into another prime (312334301404043) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156167150702024 + 156167150702025.

It is an arithmetic number, because the mean of its divisors is an integer number (156167150702025).

Almost surely, 2312334301404049 is an apocalyptic number.

It is an amenable number.

312334301404049 is a deficient number, since it is larger than the sum of its proper divisors (1).

312334301404049 is an equidigital number, since it uses as much as digits as its factorization.

312334301404049 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 373248, while the sum is 41.

The spelling of 312334301404049 in words is "three hundred twelve trillion, three hundred thirty-four billion, three hundred one million, four hundred four thousand, forty-nine".