Base | Representation |
---|---|
bin | 101101011100110110001… |
… | …011001001001101000101 |
3 | 102001120220122021100222010 |
4 | 231130312023021031011 |
5 | 402133110112141031 |
6 | 10350503000324433 |
7 | 441440345636034 |
oct | 55346613111505 |
9 | 12046818240863 |
10 | 3123350115141 |
11 | aa46727949a3 |
12 | 4253ab773719 |
13 | 1986b8ac5209 |
14 | ab25714271b |
15 | 563a389b246 |
hex | 2d7362c9345 |
3123350115141 has 16 divisors (see below), whose sum is σ = 4267025820288. Its totient is φ = 2030977401600.
The previous prime is 3123350115133. The next prime is 3123350115169. The reversal of 3123350115141 is 1415110533213.
3123350115141 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 3123350115141 - 23 = 3123350115133 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3123350115099 and 3123350115108.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3123350114141) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2402040 + ... + 3466481.
It is an arithmetic number, because the mean of its divisors is an integer number (266689113768).
Almost surely, 23123350115141 is an apocalyptic number.
It is an amenable number.
3123350115141 is a deficient number, since it is larger than the sum of its proper divisors (1143675705147).
3123350115141 is a wasteful number, since it uses less digits than its factorization.
3123350115141 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5872892.
The product of its (nonzero) digits is 5400, while the sum is 30.
Adding to 3123350115141 its reverse (1415110533213), we get a palindrome (4538460648354).
The spelling of 3123350115141 in words is "three trillion, one hundred twenty-three billion, three hundred fifty million, one hundred fifteen thousand, one hundred forty-one".
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