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312345363543213 = 3711313233773101137
BaseRepresentation
bin100011100000100111001001…
…0011100001111010010101101
31111221220220222102110110222210
41013001032102130033102231
5311414431301031340323
63024145251253401033
7122535131166255120
oct10701162234172255
91457826872413883
10312345363543213
1190582a19991000
122b04675a339179
131053906cc4cb60
14571b84c1ba3b7
152619c4673d293
hex11c139270f4ad

312345363543213 has 1024 divisors, whose sum is σ = 623052878708736. Its totient is φ = 135127719936000.

The previous prime is 312345363543127. The next prime is 312345363543217.

312345363543213 is nontrivially palindromic in base 10.

It is not a de Polignac number, because 312345363543213 - 224 = 312345346765997 is a prime.

It is a super-2 number, since 2×3123453635432132 (a number of 30 digits) contains 22 as substring.

Its product of digits (6998400) is a multiple of the sum of its prime divisors (405).

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (312345363543217) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 1023 ways as a sum of consecutive naturals, for example, 2279893164481 + ... + 2279893164617.

It is an arithmetic number, because the mean of its divisors is an integer number (608450076864).

Almost surely, 2312345363543213 is an apocalyptic number.

312345363543213 is a gapful number since it is divisible by the number (33) formed by its first and last digit.

It is an amenable number.

312345363543213 is a deficient number, since it is larger than the sum of its proper divisors (310707515165523).

312345363543213 is a wasteful number, since it uses less digits than its factorization.

312345363543213 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 427 (or 405 counting only the distinct ones).

The product of its digits is 6998400, while the sum is 48.

It can be divided in two parts, 3123453 and 63543213, that added together give a palindrome (66666666).

The spelling of 312345363543213 in words is "three hundred twelve trillion, three hundred forty-five billion, three hundred sixty-three million, five hundred forty-three thousand, two hundred thirteen".