Base | Representation |
---|---|
bin | 1110001101001101110110… |
… | …11000111010011011101111 |
3 | 11002121120001001022020102212 |
4 | 13012212323120322123233 |
5 | 13043320410344421444 |
6 | 150235354355041035 |
7 | 6403022152135160 |
oct | 706467330723357 |
9 | 132546031266385 |
10 | 31240441013999 |
11 | 9a54aa6574568 |
12 | 36067345a017b |
13 | 1457c6527b029 |
14 | 7a008c881767 |
15 | 39298006219e |
hex | 1c69bb63a6ef |
31240441013999 has 8 divisors (see below), whose sum is σ = 36377009483040. Its totient is φ = 26272284626016.
The previous prime is 31240441013851. The next prime is 31240441014011. The reversal of 31240441013999 is 99931014404213.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 31240441013999 - 216 = 31240440948463 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (31240441013399) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 42103019864 + ... + 42103020605.
It is an arithmetic number, because the mean of its divisors is an integer number (4547126185380).
Almost surely, 231240441013999 is an apocalyptic number.
31240441013999 is a deficient number, since it is larger than the sum of its proper divisors (5136568469041).
31240441013999 is an equidigital number, since it uses as much as digits as its factorization.
31240441013999 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 84206040529.
The product of its (nonzero) digits is 839808, while the sum is 50.
The spelling of 31240441013999 in words is "thirty-one trillion, two hundred forty billion, four hundred forty-one million, thirteen thousand, nine hundred ninety-nine".
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